diffYearsAvg
diffYearsAvg returns the difference in years (defined as 365.2425 days to compensate for leap years) between two date-time values, as a double.
Syntax
diffYearsAvg(start, end)
Parameters
| Parameter | Type | Description |
|---|---|---|
| start | Instant | The start time of the range. |
| start | ZonedDateTime | The start time of the range. |
| end | Instant | The end time of the range. |
| end | ZonedDateTime | The end time of the range. |
Returns
Returns the difference in years between the supplied start and end values.
Examples
d1 = parseInstant("2022-01-01T00:00:00 ET")
d2 = parseInstant("2028-01-02T00:00:00 ET")
difference = diffYearsAvg(d1, d2)
println difference